![]() ![]() You will allways find fretting postion on fretboard where plucked string produces lets say C note, but that postion would shift up and down the fretboard depending on string tension. So, pitch is not afected by air temp.Īnd another way to look at it. ![]() That would cause tiny random vibrato, and that is real issue, but effect is so small (because it depends on derivate of air temp) that only practical effect is that impulse response reverbs dont sound like real rooms because of large distance traveled during all that bouncing around the walls (btw, this effect is real, and rooms do "breathe" - I've done some dereverberation algos, and it's big issue in such cases). What would be an issue is if air temperature would shift during wave travel to listener. That wavelenght would depend on sound velocity, and thus air temeperature, but time between same positions on waveform would be the same, and thus frequency of wave, since timing is governed by initial oscilating body. Depending on air temeperature, initial wavefront would have traveled certain distance from string, that would be wavelenght in air. After ceratin amount of time string will be (almost) back to initial position after strike, that time would be first full period of wave. When string starts to move after initial disposition it creates ripple - wavefront in sorounding air. So I am extending that to assume that the Peterson is "listening" to the wavelengths and so a shorter wavelength would appear to be a higher pitch, and a lower wavelength would appear to be a lower pitch.Ĭlick to expand.yes. So therefore, in cold weather, the frequency that is leaving the marimba key is a shorter wavelength than it is when it is hotter, right? If I want it to resonate at the normal pitch, I need to shorten the tube. ![]() Now when it gets cold outside, that resonator tube goes flat-meaning that I would have to play a lower pitch in order to achieve that resonance. The key is struck, and the frequency wave goes down the resonator and bounces off the bottom and when it reaches the top of the tube, the wavelength is at its widest point, so creates the resonance. What is throwing me off is when You tune a resonator tube to be in tune with a pitch, you make the tube to be 1/4 the wavelength of the pitch. It vibrates at the frequency that it is tuned to. So I understand that the pitch is formed inside the key when struck. I understand that I'm incorrect, and I'm still trying to wrap my head around what is wrong with my thinking, so please bare with me and point out where I am going astray: Thank you for your replies, and for helping me try to understand this dilema. ![]()
0 Comments
Leave a Reply. |